Questions
A photon materializes into an electron-positron pair. The kinetic energy of the electron is found to be 0.19MeV. What was the energy of the photon?
a
0.38MeV
b
0.70MeV
c
1.40MeV
d
1.0MeV
detailed solution
Correct option is C
Conservation of Energy, Photon →e++e−+energy EP=Ere++Ere−+K.E. of both (e−+e+)Rest mass energy of e+ or e−=mc2=(11823)931.5MeV=0.51MeV Hence, EP=0.51+0.51+0.19×2=1.40MeVTalk to our academic expert!
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