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Q.

Photon is quantum of radiation with energy E = hv, where y is frequency and h is Planck's constant. The dimensions of h are the same as that of

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a

linear impulse

b

angular impulse

c

linear momentum

d

angular momentum

answer is B.

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Detailed Solution

we know that energy of radiation, E = hv. So, we have to comp arc h with dimensional formula of each option.[h]=[E][v]= Force × Displacement  Frequency =M1L2T−2T−1=M1L2T−1(1) Dimension of linear impulse      [I]=[Ft]=MLT−2[T]=MLT−1Where t is the time interval.(2) Dimension of angular impulse      [J]=[Iω]=ML2T−1=ML2T−1(3) Dimensi6n of linear momentum     [P]=[mv]=[M]LT−1=MLT−1(4) Dimension of angular momentum    [L]=[mvr]=[M]LT−1[L]=ML2T−1Hence, dimension of angular impulse and angular momentum is same as Planck's constant (h).
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