Photon is quantum of radiation with energy E = hv, where y is frequency and h is Planck's constant. The dimensions of h are the same as that of
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
linear impulse
b
angular impulse
c
linear momentum
d
angular momentum
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
we know that energy of radiation, E = hv. So, we have to comp arc h with dimensional formula of each option.[h]=[E][v]= Force × Displacement Frequency =M1L2T−2T−1=M1L2T−1(1) Dimension of linear impulse [I]=[Ft]=MLT−2[T]=MLT−1Where t is the time interval.(2) Dimension of angular impulse [J]=[Iω]=ML2T−1=ML2T−1(3) Dimensi6n of linear momentum [P]=[mv]=[M]LT−1=MLT−1(4) Dimension of angular momentum [L]=[mvr]=[M]LT−1[L]=ML2T−1Hence, dimension of angular impulse and angular momentum is same as Planck's constant (h).