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Q.

A photon of wavelength 4400 Å is passing through vacuum. The effective mass and momentum of the photon are respectively

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a

5×10−36kg,1.5×10−27kg−m/s

b

5×10−35kg,1.5×10−26kg−m/s

c

Zero, 1.5×10−26kg−m/s

d

5×10−36kg,1.67×10−43kg−m/s

answer is A.

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Detailed Solution

p=hλ=6.6×10−344400×10−10=1.5×10−27kg⋅m/s and mass m=pc=1.5×10−273×108=5×10−36kg
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