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A photosensitive material is at 9 m to the left of the origin and the source of light is at 7 m to the right of the origin along x-axis. The photosensitive material and the source of light start from rest and move, respectively, with 8i^ m s-1 and 4i^ ms-1. The ratio of intensities at t=0 to t=3 s as received by the photosensitive material is

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a

16:1

b

1:16

c

2:7

d

7:2

answer is B.

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Detailed Solution

The separation between source and photosensitive material at t:0 is 16 m. Therefore, intensity received by photosensitive material at t=0 is I0=P/4π×162,where P is the power of source of light.At t: 3 s, the source is at (15, 0) and detector is at (19, 0), so the separation between them is 4 m.I2=P4π×42 So, I1I2=116

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A photosensitive material is at 9 m to the left of the origin and the source of light is at 7 m to the right of the origin along x-axis. The photosensitive material and the source of light start from rest and move, respectively, with 8i^ m s-1 and 4i^ ms-1. The ratio of intensities at t=0 to t=3 s as received by the photosensitive material is