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Q.

A photosensitive metallic surface has work function, hvo. If photons of energy 2hvo fall on this surface, the electrons come out with a maximum velocity of 4 x 106 m./s. When the photon energy is increased to 5hvo, then maximum velocity of photoelectrons will be

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a

2 x 106 m./s

b

2 x 107 m./s

c

8 x 105 m./s

d

8 x 106 m./s

answer is D.

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Detailed Solution

Einstein's photoelectric equation can be written as12mv2=hv−ϕ⇒12m×4×1062=2hvo−hvo  .     .   iand     12m×v2=5hvo−hvo    .     .     .      .     .   iiDiving  Eq.ii  by  i,  we  get  v24×1062=4hvohvo⇒v2=4×16×1012⇒v2=64×1012⇒v=8×106m/s
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