A physical parameter a can be determined by measuring the parameters b, c, d and e using the relation a = bαcβ/dγeδ . If the maximum errors in the measurement of b, c, d and e are b1%, c1%, d1% and e1%then the maximum error in the value of a determined by the experiment is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
(b1+c1+d1+e1%)
b
(b1+c1-d1-e1)%
c
(αb1+βc1-γd1-δe1)%
d
(αb1+βc1+γd1+δe1)%
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
a = bαcβ/dγeδSo maximum error in a is given by(∆aa×100)max = α.∆bb×100+β∆cc×100+γ.∆dd×100+δ.∆ee×100= (αb1+βc1+γd1+δe1)%
A physical parameter a can be determined by measuring the parameters b, c, d and e using the relation a = bαcβ/dγeδ . If the maximum errors in the measurement of b, c, d and e are b1%, c1%, d1% and e1%then the maximum error in the value of a determined by the experiment is