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Q.

A physical parameter a can be determined by measuring the parameters b, c, d and e using the relation a=bαcβ/dγeδ. If the maximum errors in the measurement of b, c, d and e are b1%,c1%,d1% and e1%, then the maximum error in the value of a determined by the experiment is

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a

b1+c1+d1+e1%

b

b1+c1−d1−e1%

c

αb1+βc1−γd1−δe1%

d

ab1+βc1+γd1+δe1%

answer is D.

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Detailed Solution

a=bαcβ/dγeδSo, maximum error in a is given byΔaa×100max=α⋅Δbb×100+β⋅Δcc×100+γ⋅Δdd×100+δ⋅Δee×100=αb1+βc1+γd1+δe1%
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