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Q.

A physical parameter a is given as a=bαcβdγeδ.  What is the maximum error in value of a if the maximum errors in the measurement of b, c, d and e are b1%, c1%, d1% and e1% ?

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a

b1+c1+d1+e1%

b

b1+c1−d1−e1%

c

αb1+βc1−γd1−δe1%

d

αb1+βc1+γd1+δe1%

answer is D.

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Detailed Solution

Given expression for,a=bαcβdγejSo, maximum error in a is given byΔaa×100max=α⋅Δbb×100+β.Δcc×100+γ⋅Δdd×100+δ⋅Δee×100=αb1+βc1+γd1+δe1%
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