A physical parameter a is given as a=bαcβdγeδ. What is the maximum error in value of a if the maximum errors in the measurement of b, c, d and e are b1%, c1%, d1% and e1% ?
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a
b1+c1+d1+e1%
b
b1+c1−d1−e1%
c
αb1+βc1−γd1−δe1%
d
αb1+βc1+γd1+δe1%
answer is D.
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Detailed Solution
Given expression for,a=bαcβdγejSo, maximum error in a is given byΔaa×100max=α⋅Δbb×100+β.Δcc×100+γ⋅Δdd×100+δ⋅Δee×100=αb1+βc1+γd1+δe1%