Questions
A physical pendulum pivoted at a point executes angular oscillations. Its mass m,has its centre of mass at distance r from the point of suspension. If its moment of inertia is I, then its angular frequency is
detailed solution
Correct option is C
For a body executing simple harmonic motion, Restoring torque acting on it after a small displacement θ , about an axis, τ=−cθWe know that this results in angular oscillations which can be also related τ=Iαby the equation Equating the above two we get −cθ=IαWhere for angular oscillations α=−ω2θHence −cθ=−Iω2θ Simplifying this c=Iω2 Hence ω=cIFor angular oscillation ω=cI, where ω=2πTRestoring torque acting on a rod after a small displacement θ, about an axis passing through point of contact O with the curved path,τ=−Mgrsinθ , for small angles sinθ≈θ Therefore, τ=−cθ=−Mgrθ Hence c=Mgr. Substituting this is (1) we get ω=MgrI .Talk to our academic expert!
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A disc of radius R and mass M is pivoted at the rim and is set for small oscillations. If simple pendulum has to have the same period as that of the disc, the length of the simple pendulum should be
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