First slide

Accuracy; precision of instruments and errors in measurements

Question

A physical quantity P is given by $P = \frac{A^{3} B^{1 / 2}}{C^{- 4} D^{3 / 2}}$ The quantity which brings in the maximum percentage error in P is

Moderate

A

A
B

B
C

C
D

D

Solution

Quantity C has maximum power. So it brings maximum error in P.
$P = \frac{A^{3} B^{1 / 2}}{C^{- 4} D^{3 / 2}} P % = 3 A % + \frac{1}{2} B % + 4 C % + \frac{3}{2} D %$

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