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Q.

A physicist works in a laboratory where the magnetic field is 2 T. She wears a necklace enclosing area 0.01 m2 in such a way that the plane of the necklace is normal to the field and is having a resistance R = 0.01Ω. Because of power failure, the field decays to 1 T in time 10–3 seconds. Then what is the total heat produced in her necklace ? (T = Tesla)

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a

10 J

b

20 J

c

30 J

d

40 J

answer is A.

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Detailed Solution

H=V2tR and V=NB2−B1Acos⁡θtV=1×(1−2)×0.01×cos⁡0∘10−3=10V So, H=(10)2×10−30.01=10 J
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