A physicist works in a laboratory where the magnetic field is 4 T. She wears a necklace enclosing area 0.01 m2 in such a way that the plane of the necklace is normal to the field and is having a resistance R = 0.01 Ω. Because of power failure, the field decays to 1 T in time 10–3 seconds. Then what is the total heat produced in her necklace? (T = Tesla)

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10 J

20 J

90 J

40 J

answer is C.

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Detailed Solution

H=V2tR and V=N(B2−B1)AcosθtV=1×(4−1)×0.01×cos0o10−3=30 VSo, H=(30)2×10−30.01=90 J

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