First slide

Fluid statics

Question

A piece of gold weighs 10 g in air and 9 g in water. What is the volume of cavity? (Density of gold = 19.3 $g {cm}^{- 3})$

Moderate

A

0.282 cc
B

0.482 cc
C

0.682 cc
D

None

Solution

Actual volume of gold = $\frac{10}{19.3} = 0.518 {cm}^{3}$
Now, if V be the apparent volume of the piece of gold, then loss in weight of gold in water = weight of V volume of water
$\Rightarrow 10 - 9 = V \times 1 = 1 cc$
Volume of cavity = 1-0.518 = 0.482 cc

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App