A piece of ice of mass $$100$$ g and at temperature $$00C$$ is put in $$200$$ g of water at $$250C$$. How much ice will meltas the temperature of water reaches $$00C$$ ? (Take$$, latent heat of fusion of ice $$=$$ $$3.4$$ X $$105$$ $$Jkg-1) [UK PMT $$2015$$]

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Infinity Learn · Accepted Answer

Given, mass of $$ice-piece$$, $$m1$$ $$=$$ $$100$$ g $$=$$ $$0.1$$ kgMass of water, $$m2$$ $$=$$ $$200$$ g $$=$$ $$0.2$$ kgWhen temperature of mixture is $$00C$$, then heat lost by water,$$Q=m2c($$Δθ$$)=0.2$$×$$4200(25$$−$$0)$$     $$($$∵ Specific heat of water $$=$$ $$4200$$ $$J)$$⇒ Q $$=$$ $$21000JNow$$, mass of melted ice,  m'$$=QL=210003.4$$×$$105$$≃$$61.8g$$

A piece of ice of mass 100 g and at temperature 0⁰C is put in 200 g of water at 25⁰C. How much ice will melt
as the temperature of water reaches 0⁰C ? (Take, latent heat of fusion of ice = 3.4 X 10⁵ Jkg^-1) [UK PMT 2015]

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A piece of ice of mass 100 g and at temperature 00C is put in 200 g of water at 250C. How much ice will meltas the temperature of water reaches 00C ? (Take, latent heat of fusion of ice = 3.4 X 105 Jkg-1) [UK PMT 2015]

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Ready to Test Your Skills?

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A piece of ice of mass 100 g and at temperature 0⁰C is put in 200 g of water at 25⁰C. How much ice will melt
as the temperature of water reaches 0⁰C ? (Take, latent heat of fusion of ice = 3.4 X 10⁵ Jkg^-1) [UK PMT 2015]