First slide

Change of state

Question

A piece of ice of mass 50 kg is pushed with a velocity of 5 m/s along a horizontal surface. As a result of friction between the piece and the surface, the piece stops after
travelling 25 m; the ice melted in this process is:

Moderate

A

50 kg
B

50 g
C

7.86 g
D

1.86 g

Solution

Ice melted $= \frac{\frac{1}{2} {MV}^{2}}{L_{f}} = \frac{\frac{1}{2} (50) {(5)}^{2}}{80 \times 4.2 \times 1000} = 0.00186 kg = 1.86 g .$

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