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Q.

A piece of metal weighs 46 g in air. When it is immersed in a liquid of specific gravity 1.24 at 270C it weighs 30 g. When the temperature of liquid is raised to 420C the metal piece weighs 30.5 g. Specific gravity of liquid at 420C is 1.20. Calculate the coefficient of linear expansion of the metal.

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a

136200/ 0C

b

1432000/0C

c

1541000/ 0C

d

123200/ 0C

answer is B.

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Detailed Solution

W0 = mg = 46 gmat   θ1 = 270C        W1 = 30 gm = w0-B1         B1= 46-30         B1 = 16 = V1ρ1gat   θ2 = 420C   ⇒ W2 = 30.5 gm = W0-B2        B2 = 15.5 = V2ρ2g    ∴ B2B1 = V2p2V1p1         15.516 = (1+3α×15)×1.21.24        αs = [(15.516×1.241.2)-1]×145          αs = 2.31×10-5/0C = 143200/0C
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