First slide

Fluid statics

Question

A piece of solid weighs 120g in air, 80 g in water and 60 g in a liquid, then the relative density of the solid, and that of liquid are

Moderate

A

3, 2
B

2, $\frac{4}{3}$
C

$3, \frac{3}{2}$
D

4, 3

Solution

Relative density of solid = $\frac{120}{120 - 80} = 3$
Relative density of liquid = $\frac{120 - 60}{120 - 80} = \frac{60}{40} = \frac{3}{2}$

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