A piece of solid weight $$120$$ g in air $$80$$ g in water and $$60g$$ in liquid. The relative density at the solid and that at the liquid are respectively

Question

A  piece of solid weight $$120$$ g in air $$80$$ g in water and $$60g$$ in liquid. The  relative density at the solid and that at the liquid are respectively

Infinity Learn · Accepted Answer

Given  weight of solid in $$airwa=120$$ g       Weight  of solid in water $$ww=80$$ g     Weight  of solid in liquid $$wL=60$$ g     The  relative density of an object is equal to the ratio of its weight in air and  the difference of its weight in air and its weight when the object is  submerge in liquid For  relative density of solid ρ$$s=120$$ $$g120$$ $$g-80$$ $$g=12040=3$$     Hence  relative density of solid ρ$$s=3$$     How  relative density of liquid can be calculated as the ratio of loss of weight  of solid in liquid to the loss f weight in watere.g.,  relative density of liquid ρ$$L=120$$−$$60120$$−$$80$$     ρ$$L=6040=1.5$$

A piece of solid weight 120 g in air 80 g in water and 60g in liquid. The relative density at the solid and that at the liquid are respectively

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