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A piece of substance consists of two radioactive elements A and B. Initial ratio of number of active nuclei of A and B is 4 : 1. Half life of element A is T and that of element B is 2T. After what time number of active nuclei of A will be equal to that of B?

a
2T
b
8T
c
4T
d
T

detailed solution

Correct option is C

Initial number of active nucleus of A = 4N0Initial number of active nucleus of B = N0After time t, NA=4N0(2)t/T  and NB=N0(2)t/TWhen NA=NB , 4N0(2)t/T=N0(2)t/2T⇒(2)t2T+2=(2)t/T⇒tT=t2T+2⇒t=4T

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