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Q.

A piece of wood of relative density 0.36 floats in oil of relative density 0.90. the fraction of volume of wood above the surface of oil is

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a

0.3

b

0.4

c

0.6

d

0.8

answer is C.

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Detailed Solution

Fraction of body inside is ρbodyρliquid=0.360.90=0.4 So, fraction outside is1−finside=1−0.4=0.6
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