Questions
A pipe 30 cm long is open at both ends. Which harmonic mode of the pipe is resonantly excited by a 1.1 kHz source ? (Take speed of sound in air = 330 ms–1)
detailed solution
Correct option is B
Fundamental frequency (first harmonic) of open pipe n1=v2l=3302×0.3=550 HzSecond harmonic = 2×n1=1100 Hz=1.1 kHzTalk to our academic expert!
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A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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