A piston of cross-sectional area 100 cm2 is used in a hydraulic pressure to exert a force of 107 dyne on the water. The cross-sectional area of the other piston which supports an object having a mass of 2000 kg is

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9.8×102cm2

9.8×103cm2

1.96×103cm2

1.96×104cm2

answer is D.

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Detailed Solution

∵F1A1=F2A2 (Pascal's law)⇒ Cross-sectional area of the other piston,A2=F2F1⋅A1=2000×9.8×105107(100)=1.96×104cm2

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