The pitch of the screw gauge is 1 mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale divisions clearly visible while 72nd division on circular coincides with the reference line. The radius of the wire is:

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0.90 mm

1.64 mm

0.82 mm

1.80 mm

answer is C.

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Detailed Solution

Diameter =MSR+LC× corrected HSR =1+0.0172−8=1.64 mm ∴ radius, r=0.82 mm

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