The pitch of the screw gauge is 1 mm and there are 100 divisions on the circular scale. When nothing is put in between the jaws, the zero of the circular scale lies 8 divisions below the reference line. When a wire is placed between the jaws, the first linear scale divisions clearly visible while 72nd division on circular coincides with the reference line. The radius of the wire is:
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a
0.90 mm
b
1.64 mm
c
0.82 mm
d
1.80 mm
answer is C.
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Detailed Solution
Diameter =MSR+LC× corrected HSR =1+0.0172−8=1.64 mm ∴ radius, r=0.82 mm