Q.

Pitch of a screw gauge is 1 mm and there are 100 divisions on it’s circular scale. When nothing is kept between the studs, the zero of the main scale is not visible and 14th division of circular scale coincides with the horizontal mark on main scale. When circular scale is rotated by one complete rotation, zero mark on main scale is still not visible, but during the second rotation zero mark becomes just visible and 10th division of circular scale is coinciding with horizontal mark on main scale. When a glass plate is placed between the studs, the circular scale lies between 8th and 9th division of main scale and 4th division of circular scale coincides with horizontal mark on main scale. Main scale division is equal to 1mm. Then

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a

Zero error is negative and its magnitude is 1.04 mm

b

Zero error is negative and its magnitude is 1.96 mm

c

Thickness of glass plate is 10.00 mm

d

Number of significant digits in the measurement of thickness is 4

answer is B.

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Detailed Solution

pitch of the screw=distance moved by the screw on pitch scale No. of complete rotations of screw=1mm1=1mmLC=pitch of the screwNo. of Circularscale divisions=1mm100=0.01mmIn 1st full rotation, circular scale is moved by100 divisions. In 2nd rotation, circular scale moves by 96 more divisions.Total length of main scale for 196 division = 196×0.01mm=1.96mmZero error  = -1.96 mmThickness =[MSR+CSR(LC) ]+ correction=8+4(0.01)+1.96=8.04 + 1.96 = 10.00 mm
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