First slide
Fluid dynamics
Question

A Pitot tube is shown in figure. Wind blows in the direction shown. Air at inlet A is brought to rest, whereas its speed just outside of opening B is unchanged. The U tube contains mercury of density ρm. Find the speed of wind with respect to Pitot tube. Neglect the height difference between A and B and take the density of air as ρa.

Moderate
Solution

Bernoulli's equation between A and B gives

pAρa = pBρa+v22    v2 = 2[pA-pBρa]

Also equating pressures at horizontal level of E

pA+ρagy+ρagh = pB+ρagy'+ρagy+ρmgh   [ y' = 0]

pA+ρagh = pB+ρmgh

pA-pB = (ρm-ρa)gh

v2 = 2(ρm-ρa)ghρa

v = 2(ρm-ρa)ghρa

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