At a place, the magnitudes of the horizontal component and total intensity of the magnetic field of the earth are 0.3 and 0.6 oersted, respectively. The value of the angle of dip at this place will be
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a
60o
b
45o
c
30o
d
0o
answer is A.
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Detailed Solution
BH = 0.3 oersted, B = 0.6 oersted We have, BH=B cos ϕ⇒cos ϕ=BHB=0.30.6=12∴ϕ=60o
At a place, the magnitudes of the horizontal component and total intensity of the magnetic field of the earth are 0.3 and 0.6 oersted, respectively. The value of the angle of dip at this place will be