At a place the values of BH and BV are 0.4×10-4T and 0.3×10-4T respectively, then the angle of dip is
tan-1(0.75)
tan-1(0.5)
tan-1(0.8)
None of these
Formula: tanδ=BVBH=3×10−54×10−5=0.75 ⇒δ=tan−1(0.75)