At a place where the acceleration due to gravity is 10 m sec−2a force of 5 kg-wt acts on a body of mass 10 kg initially at rest. The velocity of the body after 4 second is
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a
5 m sec−1
b
10 m sec−1
c
20 m sec−1
d
50 m sec−1
answer is C.
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Detailed Solution
Alcceleration = Force Mass =50N10kg=5m/s2 From v=u+at=0+5×4=20 m s-2