Q.
Planck’s constant has the dimensions (unit) of
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a
Energy
b
Linear momentum
c
Work
d
Angular momentum
answer is D.
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Detailed Solution
We define energy of a photon E =hf, here h is Planck’s constant and f is the frequencyh = Ef ⇒ h = Ef = ML2T−2T−1 = ML2T−1We define angular momentum as L = Iω⇒ L = Iω = ML2T−1 = ML2T−1Hence, h = L = ML2T−1
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