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The plane of the dip circle is set in the geo-graphical meridian and the apparent dip is θ1 . It is then set in a vertical plane perpendicular to the geo graphical meridian the apparent dip becomes θ2 .The angle of declination α at that place is given by

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a

tanα=tanθ1tanθ2

b

α=tan2θ1tan2θ2

c

tanα=tanθ1tanθ2

d

tanα=tanθ2tanθ1

answer is C.

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Detailed Solution

Let say θ1 & θ2 are apparent dip in two different places.θ is true dip and α is the angle of declinationCase 1 : tanθ1=tanθcosα Case 2 : tanθ2=tanθcos(90-α) After dividing we get, tanθ1tanθ2=sinαcosα=tanα⇒tanθ1tanθ2=tanα

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