The plane of the dip circle is set in the $$geo-graphical$$ meridian and the apparent dip is θ$$1$$ . It is then set in a vertical plane perpendicular to the geo graphical meridian the apparent dip becomes θ$$2$$ .The angle of declination α at that place is given by

Question

The plane of the dip circle is set in the $$geo-graphical$$ meridian and the apparent dip is θ$$1$$ . It is then set in a vertical plane perpendicular to the geo graphical meridian the apparent dip becomes θ$$2$$ .The angle of declination α  at that place is given by

Infinity Learn · Accepted Answer

Let say θ$$1$$ & θ$$2$$ are apparent dip in two different places.θ is true dip  and α is the angle of declinationCase $$1$$ :   $$tan$$θ$$1=$$$$tan$$θ$$cos$$α   Case $$2$$ :  $$tan$$θ$$2=$$$$tan$$θ$$cos$$(90-$$α$$)              After dividing we get, $$tan$$θ$$1tan$$θ$$2=$$$$sin$$α$$cos$$α$$=$$$$tan$$α⇒$$tan$$θ$$1tan$$θ$$2=$$$$tan$$α

The plane of the dip circle is set in the geo-graphical meridian and the apparent dip is $θ_{1}$ . It is then set in a vertical plane perpendicular to the geo graphical meridian the apparent dip becomes $θ_{2}$ .The angle of declination $α$ at that place is given by

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The plane of the dip circle is set in the geo-graphical meridian and the apparent dip is θ1 . It is then set in a vertical plane perpendicular to the geo graphical meridian the apparent dip becomes θ2 .The angle of declination α at that place is given by

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Ready to Test Your Skills?

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The plane of the dip circle is set in the geo-graphical meridian and the apparent dip is $θ_{1}$ . It is then set in a vertical plane perpendicular to the geo graphical meridian the apparent dip becomes $θ_{2}$ .The angle of declination $α$ at that place is given by