The plane of the dip circle is set in the geographical meridian and the apparent dip is θ1. It is then set in a vertical plane perpendicular to the geographical meridian, the apparent dip becomes θ2. The angle of declination α at that place is given by
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a
tan α=tan θ1 tanθ2
b
α=tan2 θ1 tan2 θ2
c
tan α=tan θ1tanθ2
d
tan α=tan θ2tanθ1
answer is C.
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Detailed Solution
tan θ1=tan δcos θ ; tan θ2=tan δcos(90-α)tan θ1tan θ2=sin αcos α=tan α
The plane of the dip circle is set in the geographical meridian and the apparent dip is θ1. It is then set in a vertical plane perpendicular to the geographical meridian, the apparent dip becomes θ2. The angle of declination α at that place is given by