Questions
A plane electromagnetic wave of frequency 25 MHz travels in free space along the x-direction. At a particular point in space and time, electric field is . Strength of the magnetic field at this point
detailed solution
Correct option is B
GivenFrequency of electro magnetic wave=25 MHz=25×106 HzElectric field E→=6.3j^ V/mc=EB ⇒B=Ec=6.33×108=2.1×10−8 TAlso velocity of EMW is along E→×B→, so direction of magnetic field is given by v→×E→ = i^×j^=k^Talk to our academic expert!
Similar Questions
The transmitting antenna of a radio-station is mounted vertically. At a point 10 km due north of the transmitter the peak electric field is 10-3 V/m. The amplitude of the radiated magnetic field is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests