Q.

A plane electromagnetic wave of frequency 25 MHz travels in free space along the  x-direction. At a particular point in space and time, electric field is E→=6.3j^ V/m. Strength of the magnetic field at this point

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a

−2.1×10−8k^ T

b

2.1×10−8k^ T

c

2.1×10−8i^ T

d

2.1×10−8j^ T

answer is B.

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Detailed Solution

GivenFrequency of electro magnetic wave=25 MHz=25×106 HzElectric field E→=6.3j^ V/mc=EB ⇒B=Ec=6.33×108=2.1×10−8 TAlso velocity of EMW is along E→×B→, so direction of magnetic field is given by v→×E→ = i^×j^=k^
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