Questions
A plane electromagnetic wave, has frequency of and its energy density is in vacuum. The amplitude of the magnetic field of the wave is close to
:
detailed solution
Correct option is C
Energy density =B022μ0=B02∈02μ0∈0=B02C2∈02 asC2=1μ0∈0⇒B0=1C2Energy density∈0⇒B0=13×1082×1.02×10−84π∈04π=13×1082×1.02×10−8×9×109×4π=160.11×10−9TTalk to our academic expert!
Similar Questions
In a region of free space the electric field at some instant of time is and the magnetic field is . The pointing vector for these fields is
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