Q.

For a plane electromagnetic wave, the magnetic field at a point x  and time t is  B→x,t=1.2× 10−7 sin0.5× 103x+1.5× 1011tk^TThe instantaneous electric field E→ corresponding to B→  is ( speed of light c=3× 108ms−1)

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a

E→(x,t) =36 sin1× 103x+ 0.5 × 1011t j^Vm

b

E→(x,t) =36 sin 0.5 × 103x+1.5× 1011t i^Vm

c

E→(x,t) =−36 sin 0.5 × 103x+1.5× 1011t j^Vm

d

E→(x,t) =36 sin 0.5 × 103x+1.5× 1011t k^Vm

answer is C.

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Detailed Solution

Eo=cBo=36Vm​E^=B^×C^=k^×−i^=−j^Also E-field and B-field should be mutually perpendicular and have the same frequency and wavelength as they both represents the  same wave.Therefore correct key is option : 3
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