Q.
For a plane electromagnetic wave, the magnetic field at a point x and time t is B→x,t=1.2× 10−7 sin0.5× 103x+1.5× 1011tk^TThe instantaneous electric field E→ corresponding to B→ is ( speed of light c=3× 108ms−1)
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a
E→(x,t) =36 sin1× 103x+ 0.5 × 1011t j^Vm
b
E→(x,t) =36 sin 0.5 × 103x+1.5× 1011t i^Vm
c
E→(x,t) =−36 sin 0.5 × 103x+1.5× 1011t j^Vm
d
E→(x,t) =36 sin 0.5 × 103x+1.5× 1011t k^Vm
answer is C.
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Detailed Solution
Eo=cBo=36VmE^=B^×C^=k^×−i^=−j^Also E-field and B-field should be mutually perpendicular and have the same frequency and wavelength as they both represents the same wave.Therefore correct key is option : 3
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