For a plane electromagnetic wave, the magnetic field at a point $x$ and time t is
$\vec{B} (x, t) = [1.2 \times 10^{- 7} \sin (0.5 \times 10^{3} x + 1.5 \times 10^{11} t) \hat{k}] T$
The instantaneous electric field $\vec{E}$ corresponding to $\vec{B}$ is ( speed of light $c = 3 \times 10^{8} m s^{- 1})$

Question

Infinity Learn · Accepted Answer

$$Eo=cBo=36Vm$$​$$E^=B^$$×$$C^=k^$$×−$$i^=$$−$$j^Also$$ $$E-field$$ and $$B-field$$ should be mutually perpendicular and have the same frequency and wavelength as they both represents the  same wave.Therefore correct key is option : $$3$$

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For a plane electromagnetic wave, the magnetic field at a point x and time t is B→x,t=1.2× 10−7 sin0.5× 103x+1.5× 1011tk^TThe instantaneous electric field E→ corresponding to B→ is ( speed of light c=3× 108ms−1)

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