Questions
A plane electromagnetic wave is propagating through free space. If amplitude of electric field is 50 v/m, the intensity of the wave is
a
6.8 W/m2
b
12.5 W/m2
c
3.3 W/m2
d
2.1 W/m2
detailed solution
Correct option is C
Average energy density u¯=12ε0Em2∴Average intensityI=u¯c=12ε0cEm2⇒I=12×8.85×10−12×3×108×502W/m2=3.3W/m2Talk to our academic expert!
Similar Questions
Ratio of intensities of two waves are given by 4 : 1' Then the ratio of the amplitudes of the two waves is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
free study material
JEE
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests
Popular Books
HC Verma Part 1HC Verma Part 2RS AgarwalRD SharmaLakhmir SinghDK GoelSandeep GargTS GrewalNCERT solutions
Class 12 NCERT SolutionsClass 11 NCERT SolutionsClass 10 NCERT SolutionsClass 9 NCERT SolutionsClass 8 NCERT SolutionsClass 7 NCERT SolutionsClass 6 NCERT Solutions
