A plane electromagnetic wave is propagating through vacuum. If E→$$=E0sin$$⁡$$($$ωt−$$kz)i^$$ and the wave is propagating along positive $$z-axis$$, then at that instant, magnetic field vector is given by

Correct option is 4B→=(E0C)sin⁡(ωt−kz)j^

Questions

A plane electromagnetic wave is propagating through vacuum. If $\vec{E} = E_{0} \sin (ωt - kz) \hat{i}$ and the wave is propagating along positive z-axis, then at that instant, magnetic field vector is given by

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B→=CE0cos⁡(ωt−kz)j^

B→=(E0C)sin(ωt+kz)j^

B→=CE0sin⁡(ωt+kz)(−j^)

B→=(E0C)sin⁡(ωt−kz)j^

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detailed solution

Correct option is D

E→ and B→ are always in phase and EB=C,Also direction of propagation of wave is same as the direction of E→×B→.

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A plane electromagnetic wave is propagating through vacuum. If E→=E0sin⁡(ωt−kz)i^ and the wave is propagating along positive z-axis, then at that instant, magnetic field vector is given by

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Ready to Test Your Skills?

free study material

A plane electromagnetic wave is propagating through vacuum. If $\vec{E} = E_{0} \sin (ωt - kz) \hat{i}$ and the wave is propagating along positive z-axis, then at that instant, magnetic field vector is given by