First slide

Projection Under uniform Acceleration

Question

A plane flying horizontally at 100 ms^-1 releases ah object which reaches the ground in 10 s. At what angle with horizontal it hits the ground?

Easy

A

55^o
B

45^o
C

60^o
D

75^o

Solution

$v_{x} = u_{x} = 100 {ms}^{- 1}, v_{x} = u_{x} + ayt = 0 + 10 \times 10 tanθ = \frac{v_{y}}{v} = \frac{100}{100} = 1 \Rightarrow θ = 45 °$

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