A plane mirror is lying in xy-plane with its reflecting surface facing positive z-axis. A particle is moving towards the reflecting surface of the mirror with velocity 2i^−2j^−3k^m/s. If the mirror starts moving with velocity 2k^ m/s, velocity of the image of the particle relative to the mirror is

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2i^−2j^−5k^m/s

2i^+2j^+5k^m/s

−2i^+2j^+5k^m/s

2i^−2j^+5k^m/s

answer is D.

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Detailed Solution

Velocity of the particle relative to the mirror is given by, V→P/M=V→P−V→M=2i^−2j^−5k^m/sTherefore velocity of the image relative to the mirror is, V→i/M=2i^−2j^+5k^m/s.

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