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Q.

On a planet a body is left fall freely from a height 2 metres reaches the ground 2  seconds if the length of a simple pendulum is 2 metres on that planet, its time period is

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a

3.14 seconds

b

6.28 seconds

c

1.57 seconds

d

4.17 seconds

answer is B.

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Detailed Solution

h=12gt2 given length of the pendulum l=2m, give time of fall t=2sec2=12gp22gp=42=2 m/sec2Time period T=2πlg=2π22=2π=2(3.14)    T=6.28 seconds
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