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On a planet a body is left fall freely from a height 2 metres reaches the ground 2  seconds if the length of a simple pendulum is 2 metres on that planet, its time period is

a
3.14 seconds
b
6.28 seconds
c
1.57 seconds
d
4.17 seconds

detailed solution

Correct option is B

h=12gt2 given length of the pendulum l=2m, give time of fall t=2sec2=12gp22gp=42=2 m/sec2Time period T=2πlg=2π22=2π=2(3.14)    T=6.28 seconds

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