First slide

Oscillation motion

Question

On a planet, a body is let fall freely from a height 8m reaches the ground in 2 sec. If the length of a simple pendulum is 1m on that planet, its time period is

Easy

A

3.14 sec
B

6.24 sec
C

1.57 sec
D

4.71 sec

Solution

$\large s\, = \,ut + \frac{1}{2}a{t^2}\, \Rightarrow \,8\, = \,0 + \frac{1}{2}{g_p} \times 4$
$\large {g_p}\, = \,4m/{\sec ^2}$
$\large T\, = \,2\pi \sqrt {\frac{1}{4}} \, = \,\frac{{2\pi }}{2}\, = \,\pi \sec \, = \,3.14\sec$

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