First slide

Acceeleration due to gravity on surface of planet

Question

A planet has twice the values of mass and radius of earth. Acceleration due to gravity on the surface of the planet is :

Easy

A

9.8 m/s²
B

4.9 m/s²
C

980 m/s²
D

19.6 m/s²

Solution

$g = \frac{G \cdot 2 M_{e a r t h}}{{(2 R_{e a r t h})}^{2}} = \frac{1}{2} \frac{G M_{e a r t h}}{{R_{e a r t h}}^{2}} = \frac{g_{e a r t h}}{2} = 4.9 m / s^{2}$

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