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Q.

Plate area of a parallel plate capacitor is 1 cm2 and plate separation is 0.1 mm. The space between the plates is completely filled by a dielectric slab of dielectric constant 3. Then capacitance of the capacitor is

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a

18.37 pF

b

26.55 pF

c

32.12 pF

d

28.75 μF

answer is B.

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Detailed Solution

C=∈​0KAd=8.85×10−12×3×10−40.1×10−3  farad⇒C=26.55​ pF
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