Questions
Plate area of a parallel plate capacitor is and plate separation is 0.1 mm. The space between the plates is completely filled by a dielectric slab of dielectric constant 3. Then capacitance of the capacitor is
detailed solution
Correct option is B
C=∈0KAd=8.85×10−12×3×10−40.1×10−3 farad⇒C=26.55 pFTalk to our academic expert!
Similar Questions
A parallel plate, air filled capacitor has capacitance C. When a dielectric material of dielectric constant 4 is filled so that half of the space between plates is occupied by it, then percentage increase in the capacitance is equal to
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