First slide

Capacitance

Question

Plate area of a parallel plate capacitor is $1 c m^{2}$ and plate separation is 0.1 mm. The space between the plates is completely filled by a dielectric slab of dielectric constant 3. Then capacitance of the capacitor is

Easy

A

18.37 pF
B

26.55 pF
C

32.12 pF
D

28.75 $μ F$

Solution

$C = \frac{{∈}_{0} K A}{d} = {\frac{8.85 \times 10^{- 12} \times 3 \times 10^{- 4}}{0.1 \times 10^{- 3}}}_{}$ farad
$\Rightarrow C = 26.55 p F$

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