First slide

Electrostatic potential

Question

The plate area and plate seperation of a parallel plate capacitor are 10 mm² and 0.2 mm. The capacitor is connected to a battery of emf 10 volt. Now a dielectric slab of dielectric constant k = 4 is inserted into the capacitor. Then intensity of electric field inside the dielectric slab will be

Easy

A

12500 v/m
B

30000 v/m
C

2500 v/m
D

50000 v/m

Solution

$E = \frac{p . d . between the plates}{plate sep a ration} = \frac{10}{0.2 x 10^{- 3}} v / m = 50000 v / m$
inside the dielectric it decreases by k times
$\frac{50000}{4} = 12500$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App