The plate area and plate seperation of a parallel plate capacitor are 10 mm2 and 0.2 mm. The capacitor is connected to a battery of emf 10 volt. Now a dielectric slab of dielectric constant k = 4 is inserted into the capacitor. Then intensity of electric field inside the dielectric slab will be
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a
12500 v/m
b
30000 v/m
c
2500 v/m
d
50000 v/m
answer is A.
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Detailed Solution
E=p.d. between the platesplate separation=100.2 x 10-3v/m=50000 v/minside the dielectric it decreases by k times500004=12500