Q.
A plate of mass M remains in equilibrium in air when n bullets are fired per second on it. The mass of each bullet is m and it strikes the plate with speed v' If the coefficient of restitution is e, then (M>>m)
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a
M=nm(1+e)Vg
b
M=nmvg
c
M=2nme+e2g
d
M=2nmg
answer is A.
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Detailed Solution
see fig. (4) the change in momentum of Bullet = m v e - (-m v) = m v (1+e)given that n bullets strike per second '. Force exerted by the bullets =n[mv(1+e)] upwards Now n[mv(1+e)]=Mg (∵F=Mg downwards ) so, M=nmv(1+e)g
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