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Q.

The plate separation in a parallel plate condenser is d and plate area is A. If it is charged to V volts, then the work done in increasing the plate separation to 2 d will be

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a

ε0AV22d

b

ε0A2V2d

c

ε0AV2d

d

ε0A2Vd

answer is B.

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Detailed Solution

The work done W is given byW=U2−U1Here, U1=12CV2and  U2=12C2(2V)2=CV2∴ W=CV2−12CV2=12CV2=12ε0AdV2=ε0AV22d
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