A plate of thickness 't' made of a material of refractive index 'μ' is placed in front of one of the slits in a double slit experiment. What should be the minimum thickness 't', which will make the intensity at the centre of the fringe pattern zero?
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a
μ−1λ2
b
λμ−1
c
λ2μ−1
d
μ−1λ
answer is C.
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Detailed Solution
Intensity at the centre of the pattern will be zero,if path difference at the centre is λ2.Now, the path difference introduced by glass plate of thickness 't' is μ−1t∴μ−1t=λ2 or t=λ2μ−1.Therefore, the correct answer is (C).