A plate of Thickness ‘t’ made of a material of refractive index μ is placed in front of one of the slits in a double slit experiment. What should be the minimum thickness ‘t’ which will make the intensity at the center of fringe pattern zero?
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answer is 3.
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Detailed Solution
At the center of the fringe pattern, path difference = (μ−1)t∴ For dark fringe, (μ−1)t=λ2 ⇒ t=λ2(μ−1)
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A plate of Thickness ‘t’ made of a material of refractive index μ is placed in front of one of the slits in a double slit experiment. What should be the minimum thickness ‘t’ which will make the intensity at the center of fringe pattern zero?