Questions
The plates of a parallel plate capacitor are charged up to 100 volt. A 2 mm thick plate is inserted between the plates, then to maintain the same potential difference, the distance between the capacitor plates is increased by 1.6 m.m. The dielectric constant of the plate is
detailed solution
Correct option is A
When the dielectric slab is introduced Hence to maintain the same potential difference, the plates should be increased byt1−1K=d′21−1K=1⋅6Solving, we get K = 5Talk to our academic expert!
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A parallel plate, air filled capacitor has capacitance C. When a dielectric material of dielectric constant 4 is filled so that half of the space between plates is occupied by it, then percentage increase in the capacitance is equal to
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