Q.
Plates of a parallel plate capacitor of capacitance 4μF is connected to the terminals of a battery of 12 volt. Now the battery is disconnected from the capacitor and the plates of the capacitor are connected to the plates of a 1μF parallel plate uncharged capacitor. If a dielectric slab of dielectric constant k = 2 is introduced into the space between the plates of 1μF capacitor, The potential difference across the combination of capacitors is
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a
7.5 volt
b
4 volt
c
6 volt
d
8 volt
answer is D.
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Detailed Solution
Q = Charge on the combination of capacitors =4 x 12 μC=48μCCe = Equivalent capacitance =4+1 x 2μF=6μF∴V'=QCe=486volt=8 volt