Q.

Plates of a parallel plate capacitor of capacitance 4μF is connected to the terminals of  a battery of 12 volt. Now the battery is disconnected from the capacitor and the plates of the capacitor are connected to the plates of a  1μF parallel plate uncharged capacitor. If a dielectric slab of dielectric constant k = 2 is introduced into the space between the plates of 1μF capacitor, The potential difference across the combination of capacitors is

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a

7.5 volt

b

4 volt

c

6 volt

d

8 volt

answer is D.

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Detailed Solution

Q = Charge on the combination of capacitors =4 x 12 μC=48μCCe = Equivalent capacitance =4+1 x 2μF=6μF∴V'=QCe=486volt=8 volt
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