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Q.

The plates of a parallel plate capacitor have an area of  90  cm2 each and are separated by 2 mm. The capacitor is charged by connecting it to a 400 V supply. Then the energy density of the energy stored  (in  Jm−3) in the capacitor is (take  ε0=8.8×10−12  Fm−1)

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a

0.113

b

0.177

c

0.152

d

none of these

answer is B.

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Detailed Solution

A=90  cm2,  d=2  mmE=Vd,  V=400 Vu=12ε0E2=12ε0(Vd)2=12(8.85×10−12)(4002×10−3)2=0.177  Jm−3
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